Cheatsheet

Complex Analysis

All topics on one page

5modules
15articles
0definitions
42formulas

01

Holomorphic Functions

Cauchy–Riemann conditions and elementary functions of a complex variable

Functions of a Complex Variable: Basic Concepts

Motivation: Why extend ℝ to ℂ? → The Complex Plane → Differentiability and Cauchy–Riemann Conditions → Holomorphic Functions → Harmonic Functions → Elementary Functions → Numerical Example → Practical Application → Connection with Other Branches of Mathematics → Historical Note and Development of the Idea

Formulas

Exponent: eᶻ = eˣ(cos y + i sin y). It is periodic with period 2πi: e^{z+2πi} = eᶻ. Note: |eᶻ| = eˣ > 0, arg eᶻ = y.Trigonometric: sin z = (eⁱᶻ − e⁻ⁱᶻ)/(2i), cos z = (eⁱᶻ + e⁻ⁱᶻ)/2. They are unbounded on ℂ!Logarithm: ln z = ln|z| + i arg z—a multivalued function. The principal value Ln z is chosen when arg z ∈ (−π, π].

In many problems of real analysis—computing integrals such as ∫₋∞^∞ dx/(1+x²), solving differential equations, potential theory—the answer is surprisingly simple, but obtaining it “directly” is hard. It turns out that all these problems are transparently solved if we extend the real number line t...

A complex number z = x + iy is identified with the point (x, y) of the plane ℝ². Here x = Re z is the real part, y = Im z is the imaginary part, i is the imaginary unit (i² = −1).

Modulus: |z| = √(x² + y²) is the distance from the origin. Argument: arg z = arctg(y/x) is the angle with the positive semi-axis (defined up to 2πk). Conjugate number: z̄ = x − iy. Important: z·z̄ = |z|².

A function f: ℂ → ℂ is a mapping from the plane to itself: f(z) = u(x,y) + iv(x,y), where u and v are real-valued functions of two real variables. For example, f(z) = z² = (x+iy)² = x²−y² + 2ixy, so u = x²−y², v = 2xy.

Conformal Mappings

Motivation: What Does a "Correct" Mapping Mean → Conformal Mapping → Möbius (Fractional-Linear) Transformations → Riemann's Theorem → Applications → Numerical Example → Real-World Application → Additional Aspects → Connection With Other Branches of Mathematics → Historical Background and Development of the Idea

Formulas

Form: $w = \frac{az+b}{cz+d}$, $ad-bc \neq 0$.Theorem (Riemann, 1851): Any simply connected domain $D \subsetneq \mathbb{C}$ is conformally equivalent to the unit disk $\mathbb{D} = \{|z| < 1\}$.
  • ·Map lines and circles to lines and circles.
  • ·Preserve the cross-ratio $(z_1,z_2;z_3,z_4) = \frac{(z_1-z_3)(z_2-z_4)}{(z_1-z_4)(z_2-z_3)}$.
  • ·Are determined by three pairs "point $\to$ image".

Many problems in mathematical physics are posed in complex domains (slits, airfoils, jagged surfaces). The method of conformal mappings allows one to transform such domains into simple regions (circle, half-plane), solve the problem there, and then map the solution back. This works because confor...

A holomorphic function $f$ with $f'(z_0) \neq 0$ is conformal at the point $z_0$: it preserves the angles between curves and their orientation.

Proof. Let $\gamma_1, \gamma_2$ be curves passing through $z_0$, $\gamma_1'(0) = v_1$, $\gamma_2'(0) = v_2$. Their images: $(f\circ\gamma_i)'(0) = f'(z_0)\cdot v_i$. Multiplication by $f'(z_0)\ne 0$ rotates both vectors by the same angle $\arg f'(z_0)$, so the angle between them is preserved. The...

This is a bijection of the extended plane $\mathbb{C}\cup\{\infty\}$ onto itself (i.e., a mapping of the Riemann sphere). Each Möbius transformation is a composition of translations, rotations, scalings, and inversion $z \mapsto 1/z$.

The Fundamental Theorem of Algebra via Complex Function Theory

Motivation: Theorems on "Global" Behavior → Liouville's Theorem → The Fundamental Theorem of Algebra → Maximum Modulus Principle → Argument Principle → Picard's Theorem → Numerical Example → Real-World Application → Connection with Other Areas of Mathematics → Historical Note and Development of the Idea

Formulas

Corollary: $P(z) = c(z - z_1)^{m_1} \cdots (z - z_k)^{m_k}$ — factorization into linear factors over $\mathbb{C}$. $m_1 + \cdots + m_k = n$.Example: $e^z$ takes all values $w \in \mathbb{C} \setminus \{0\}$: $e^z = w \iff z = \ln w$ (infinitely many solutions for $w \neq 0$).Conclusion: $P(z) = z^5 + 3z + 1$ has exactly 1 zero in the unit disk and exactly 4 zeros in the annulus $1 < |z| < 2$.

Real differentiability is a “local” property. Holomorphicity, on the contrary, imposes extremely strict global constraints: knowing the function on a small segment, one can recover it everywhere; a bounded entire function must be constant. These theorems explain why complex numbers are algebraica...

Theorem (Liouville, 1847): Any holomorphic and bounded function on all of $\mathbb{C}$ is constant.

Proof via Cauchy’s inequality: $f'(z) = \frac{1}{2\pi i} \oint_{|\zeta - z| = R} \frac{f(\zeta)}{(\zeta - z)^2} d\zeta$. Estimate: $|f'(z)| \leq M/R \to 0$ as $R \to \infty$ ($M = \sup|f|$). Thus $f' \equiv 0$, hence $f = \mathrm{const}$.

This is a fundamental result: the functions $e^{\sin(z)}$ on $\mathbb{C}$ are unbounded because they “want” to be nontrivial.

02

Integration in the Complex Plane

Cauchy integral, Cauchy’s formula, and Morera’s theorem

Cauchy Integral and Its Consequences

Motivation: Integration as Function Reconstruction → Complex Integral → Cauchy's Theorem → Cauchy Integral Formula → Morera's Theorem (Converse) → Cauchy Inequality → Numerical Example → Real Application → Additional Aspects → Relationship with Other Areas of Mathematics

Formulas

Theorem: If $f$ is holomorphic in a closed disk $\overline{D} = \{|z - z_0| \leq r\}$ with boundary $\gamma = \partial D$:Problem: Compute $\oint_{|z|=2} \frac{z^2 + 1}{z - 1}\,dz$.Step 1. $f(z) = z^2 + 1$, singular point $z_0 = 1$ lies inside the disk $|z| = 2$.

In real analysis, the integral over a closed contour of a conservative field is zero. In complex analysis, this same property—for holomorphic functions—generates something much more powerful: from the values of a function on the contour, one can exactly reconstruct its values at all interior poin...

Estimate: $|\int_\gamma f\,dz| \leq \max_{z \in \gamma} |f(z)| \cdot \text{length}(\gamma)$.

A complex integral decomposes as follows: $ \int_\gamma (u+iv)(dx + i\,dy) = \int_\gamma (u\,dx - v\,dy) + i \int_\gamma (v\,dx + u\,dy) $ — two real line integrals.

Theorem (Cauchy, 1825): If $f$ is holomorphic in a simply connected domain $D$ and $\gamma$ is a closed path in $D$:

Taylor Series and Analyticity of Holomorphic Functions

Motivation: From Integral to Power Series → The Taylor Series of a Holomorphic Function → Important Expansions → Holomorphy $\iff$ Analyticity → The Principle of Analytic Continuation → The Mean Value Theorem → Numerical Example → Practical Application → Additional Aspects → Connection with Other Areas of Mathematics

Formulas

Geometric series: $1/(1−z) = \sum_{n=0}^{\infty} z^n$ for $|z| < 1$.Exponential: $e^z = \sum_{n=0}^{\infty} \frac{z^n}{n!}$ for all $z \in \mathbb{C}$.Logarithm: $\ln(1+z) = \sum_{n=1}^{\infty} (-1)^{n+1} \frac{z^n}{n}$ for $|z| < 1$.

The Cauchy integral formula allows the computation of derivatives of all orders. From this, it immediately follows that a holomorphic function can be expanded as a convergent Taylor series—and this is an equality, not just an approximation. Holomorphy and analyticity in the complex case are the s...

Theorem: If $f$ is holomorphic in the disk $|z - z_0| < R$, then for all $z$ in this disk:

$ f(z) = \sum_{n=0}^{\infty} a_n (z - z_0)^n, \quad a_n = \frac{f^{(n)}(z_0)}{n!} = \frac{1}{2\pi i} \oint \frac{f(\zeta)}{(\zeta-z_0)^{n+1}} d\zeta. $

Radius of convergence $R = \mathrm{dist}(z_0, \partial D)$ — the distance to the nearest singular point. There is no “random” breakdown of convergence: the series converges precisely up to the nearest singularity.

Analytic Continuation

Motivation: A function "knows" itself everywhere → Uniqueness Principle → Continuation Along a Path → Riemann Surfaces and Multivaluedness → The Riemann Zeta Function → Numerical Example → Real-World Application → Additional Aspects → Connection with Other Areas of Mathematics → Historical Background and Development of the Idea

Formulas

Step 1. For |z| < 1: f(z) = 1/(1−z) (the sum of the geometric series).Step 2. Analytic continuation is simply the function 1/(1−z), defined on ℂ \ {1}. At the point z = 2: f(2) = 1/(1−2) = –1.

Holomorphic functions possess a remarkable property: knowing the function in a small domain allows one to extend it to everything permitted by analyticity. This is called analytic continuation—and it is unique. It is precisely this principle that allows the “definition” of the Riemann ζ-function ...

Theorem: If f and g are holomorphic in a connected domain D and coincide on a set with a limit point in D, then f ≡ g in D.

Corollary (analytic continuation principle): If f is holomorphic in D₁, g is holomorphic in D₂, D₁ ∩ D₂ ≠ ∅ is connected, and f = g on D₁ ∩ D₂, then g is the unique analytic continuation of f to D₂.

Physical meaning: There do not exist two different holomorphic functions that coincide even on a tiny segment. “A holomorphic object is an indivisible whole.”

03

Laurent Series and Singularities

Laurent series expansion, isolated singularities, and their classification

Laurent Series and Isolated Singular Points

Motivation: What to Do with Singular Points? → Laurent Series → Classification of Singular Points → Casorati–Weierstrass Theorem → Numerical Example → Real-world Application → Additional Aspects → Connection with Other Areas of Mathematics → Historical Note and Development of the Idea

Formulas

Regular part: $\sum_{n=0}^\infty c_n (z - z_0)^n$—converges in the disk $|z - z_0| < R$.Principal part: $\sum_{n=1}^\infty c_{-n}/(z - z_0)^n$—converges outside the disk $|z - z_0| > r$.Problem: Find the Laurent series of $e^{1/z}$ in the neighborhood of $z = 0$ and classify the singular point.

In the neighborhood of a point where a function is not defined or not holomorphic, the Taylor series is not applicable—it requires holomorphicity in a disk. The Laurent series expands this by including negative powers: $f(z) = \dots + c_{-2}/(z-z_0)^2 + c_{-1}/(z-z_0) + c_0 + c_1(z-z_0) + \dots$ ...

In an annulus $r < |z - z_0| < R$, a function $f$ that is holomorphic in the annulus is expanded as:

where the coefficients are: $c_n = \frac{1}{2\pi i} \oint_{|\zeta - z_0| = \rho} \frac{f(\zeta)}{(\zeta - z_0)^{n+1}} d\zeta$ ($r < \rho < R$).

Regular part: $\sum_{n=0}^\infty c_n (z - z_0)^n$—converges in the disk $|z - z_0| < R$. Principal part: $\sum_{n=1}^\infty c_{-n}/(z - z_0)^n$—converges outside the disk $|z - z_0| > r$.

Residue Theory

Motivation: Evaluating Difficult Integrals → The Residue of a Function → Residue Calculation Formulas → Evaluation of Real Integrals → Numerical Example → Real-World Application → Additional Aspects → Connection with Other Fields of Mathematics → Historical Background and Development of the Idea

Formulas

Simple pole: $\operatorname{Res}_{z=z_0} f = \lim_{z \to z_0} (z-z_0)\,f(z)$.Step 1. Denominator: $x^2 + 4x + 5 = (x+2)^2 + 1$. Roots: $z^2 + 4z + 5 = 0 \rightarrow z = \frac{−4 \pm \sqrt{16−20}}{2} = −2 \pm i$.Second example: Compute $\oint_{|z|=3} \frac{z^2}{z^2-1}\,dz$.

Many real integrals — from $\int_{-\infty}^{\infty} \frac{1}{1+x^2}dx$ to $\int_0^{\infty}\frac{\sin(x)}{x}\,dx$ — are difficult to compute using elementary methods. The method of residues allows one to reduce them to the calculation of a few numbers — the residues at the poles of the function. T...

Definition: The residue of $f$ at an isolated singular point $z_0$: $ \operatorname{Res}_{z=z_0} f = c_{-1} $ — the coefficient at $(z-z_0)^{-1}$ in the Laurent series.

Residue theorem: $ \oint_{\gamma} f(z) dz = 2\pi i \sum_k \operatorname{Res}_{z=z_k} f, $ where the summation is over all singular points $z_k$ inside the contour $\gamma$.

Simple pole: $\operatorname{Res}_{z=z_0} f = \lim_{z \to z_0} (z-z_0)\,f(z)$.

Principle of the Argument and Its Applications

Motivation: Counting Zeros and Poles → Principle of the Argument → Rouché's Theorem → The Open Mapping Theorem → Montel's Theorem → Numerical Example → Real-World Application → Additional Aspects → Connection with Other Areas of Mathematics → Historical Background and Development of the Idea

Formulas

Theorem: For a meromorphic function $f$ in a domain $D$, with $\gamma = \partial D$:Step 1. Try Rouché with $f = 5z^4$ (the term with the largest modulus), $g = z^6 + 2z + 1$.Step 2. By Rouché's theorem: $5z^4 + (z^6+2z+1) = f(z)$ has as many zeros in $|z| < 1$ as $5z^4$ — exactly 4 zeros (counting multiplicity).

The problem "how many zeros does a given function have in a given domain?" arises everywhere: in control theory (stability — zeros of the denominator in the right half-plane), in numerical methods (convergence of iterations), in cryptography (periods). The principle of the argument and Rouché's t...

Theorem: For a meromorphic function $f$ in a domain $D$, with $\gamma = \partial D$:

where $N$ is the number of zeros, and $P$ is the number of poles in $D$ (counted with multiplicities).

Geometric explanation: The integral equals the change in $\arg f$ when traversing $\gamma$, divided by $2\pi$; this is the winding number of the curve $f(\gamma)$ (the number of turns the image makes around the origin). Each zero contributes +1, each pole contributes −1.

04

Special Methods and Functions

Integrals with logarithms, series summation, and special functions

Additional Methods for Calculating Integrals

Motivation: Beyond Simple Fractions → Logarithmic Integrals: The “Keyhole" Contour → Summation of Series via Residues → Integral Transforms — The Mellin Transform → Special Points on the Contour → Numerical Example → Real Application → Additional Aspects → Connection with Other Branches of Mathematics → Historical Note and Development of the Idea

Formulas

Key technique: $\pi\cot(\pi z)$ has simple poles at $z = n \in \mathbb{Z}$ with residue $1$. Then:Example — Euler’s Identity: $\sum_{n=1}^\infty \frac{1}{n^2} = \frac{\pi^2}{6}.$Step 1. The function $f(z) = \frac{z^{-1/2}}{1+z}$ with $z^{-1/2} = e^{(-1/2)\ln z}$, $\ln z$ has a cut along $[0,+\infty)$.Check: Substitute $x = t^2 \to 2\int_0^\infty \frac{dt}{1 + t^2} = 2\cdot(\pi/2) = \pi$ ✓.

Not all integrals are reducible to trivial fractions. Integrals of the form $\int_0^\infty \ln(x)\cdot f(x) dx$, $\int_0^\infty x^a\cdot f(x) dx$, or sums $\sum f(n)$ require special contours and tricks. The two main methods are: the “keyhole" contour for power integrals and summation via residue...

For $\int_0^\infty x^a f(x) dx$ ($0 < a < 1$), we make a cut along $[0,+\infty)$ and integrate $f(z)\cdot z^a$ over the "keyhole" contour: a large circle $|z|=R \to$ disappears, a small $|z|=\varepsilon \to$ disappears, only the banks of the cut remain. On the upper bank $z = x$ $(x > 0)$, on the...

$\oint = \int_0^\infty x^a f(x) dx - e^{2\pi i a}\int_0^\infty x^a f(x) dx = (1 - e^{2\pi i a}) \int_0^\infty x^a f(x) dx = 2\pi i \sum \text{Res}$.

Key technique: $\pi\cot(\pi z)$ has simple poles at $z = n \in \mathbb{Z}$ with residue $1$. Then:

Special Functions via Complex Analysis

Motivation: Functions Beyond the Elementary Ones → The Gamma Function → The Beta Function → Bessel Functions → Numerical Example → Real Application → Additional Aspects → Connection with Other Branches of Mathematics → Historical Note and Development of the Idea

Formulas

Definition: $B(a,b) = \int_0^1 t^{a-1}(1-t)^{b-1} dt = \frac{\Gamma(a)\Gamma(b)}{\Gamma(a+b)}$.Step 2. $\Gamma(1/2) \cdot \Gamma(1/2) = \pi \rightarrow \Gamma(1/2)^2 = \pi$.Step 3. $\Gamma(1/2) = \sqrt{\pi} \approx 1.7725$.Compute $\Gamma(3/2)$: $\Gamma(3/2) = (1/2)\cdot\Gamma(1/2) = \sqrt{\pi}/2 \approx 0.886$.

The solution of many problems in mathematical physics — differential equations with variable coefficients — leads to functions that cannot be expressed in terms of polynomials, trigonometric functions, and exponentials. These are called *special functions*: the gamma function, Bessel functions, h...

Analytic continuation: $\Gamma(s)$ extends to $\mathbb{C} \setminus \{0, -1, -2, \ldots \}$ with simple poles at $s = 0, -1, -2, \ldots$ and residues $\operatorname{Res}_{s=-n} \Gamma = \frac{(-1)^n}{n!}$.

Functional equation: $\Gamma(s+1) = s\cdot\Gamma(s)$. Consequently: $\Gamma(n) = (n-1)!$ for natural $n$.

Reflection formula (Euler): $\Gamma(s)\cdot\Gamma(1-s) = \frac{\pi}{\sin(\pi s)}$.

Univalent Functions and Theorems on Mappings

Motivation: How Much Can Be “Distorted” by a Univalent Mapping? → The Class S — Univalent Functions → The Koebe Theorem → The Bieberbach–de Branges Theorem → Quasiconformal Mappings → Numerical Example → Real-world Application → Additional Aspects → Connection with Other Branches of Mathematics → Historical Note and Development of the Idea

Formulas

Class S: Functions $f$ that are holomorphic and univalent (injective) in the unit disk $\mathbb{D}$, normalized by $f(0) = 0$, $f'(0) = 1$.Bieberbach Conjecture (1916): For $f \in S$ with $f(z) = z + \sum a_n z^n$: $|a_n| \leq n$ for all $n \geq 2$.

The Riemann mapping theorem guarantees the existence of a conformal mapping of any simply connected domain onto the unit disk. But how "large" can the distortion be? The Bieberbach theorem (Bieberbach conjecture, proved by de Branges in 1985) gives an exact answer in terms of the expansion coeffi...

Class S: Functions $f$ that are holomorphic and univalent (injective) in the unit disk $\mathbb{D}$, normalized by $f(0) = 0$, $f'(0) = 1$.

The Koebe Function: $k(z) = \frac{z}{(1-z)^2} = z + 2z^2 + 3z^3 + \ldots$ ($a_n = n$). This is the “extremal” function in class $S$: the image $k(\mathbb{D})$ is the whole plane minus the ray $(-\infty, -1/4]$.

Theorem (Koebe's $1/4$-theorem): The image $f(\mathbb{D})$ for $f \in S$ contains the disk $|w| < 1/4$. The estimate is sharp: for $k(z)$, the image $= \mathbb{C} \setminus (-\infty, -1/4]$.

05

Entire Functions and the Laplace Transform

Weierstrass theorem, Mittag-Leffler theorem, and applications to ODEs

Weierstrass Factorization Theorem

Motivation: From Polynomials to Entire Functions → Entire Functions → Canonical Factor → Weierstrass Factorization Theorem → Numerical Example → Real Application → Additional Aspects → Connection with Other Branches of Mathematics → Historical Background and Development of the Idea

Formulas

Order of growth: $\rho = \limsup_{r \to \infty} \frac{\ln \ln M(r)}{\ln r}$, where $M(r) = \max_{|z|=r} |f(z)|$.Euler's Product: $\sin (\pi z) = \pi z \cdot \prod_{n=1}^\infty \left(1 - \frac{z^2}{n^2}\right)$.Step 1. Euler's product: $\sin(\pi z) = \pi z \cdot \prod_{n=1}^\infty \left(1 - \frac{z^2}{n^2}\right)$.Step 3. $1 = (\pi/2) \cdot \prod_{n=1}^\infty \frac{4 n^2 - 1}{4 n^2} \rightarrow \pi/2 = \prod_{n=1}^\infty \frac{4 n^2}{4 n^2 - 1}$.
  • ·Polynomials: $\rho = 0$.
  • ·$e^z$: $M(r) = e^{r}$, $\ln \ln e^r = \ln r$, $\rho = 1$.
  • ·$\sin z$: $\rho = 1$ ($|\sin z| \leq e^{|\operatorname{Im} z|}$).

A polynomial $P(z)$ of degree $n$ has exactly $n$ zeros (with multiplicities) and can be decomposed as $P(z) = c(z-z_1)\cdots(z-z_n)$. Can we similarly "decompose" an entire function with infinitely many zeros? The Weierstrass theorem gives an affirmative answer, but with a caveat: to ensure the ...

An entire function is one that is holomorphic on all of $\mathbb{C}$. Examples: polynomials, $e^z$, $\sin z$, $\cos z$.

Order of growth: $\rho = \limsup_{r \to \infty} \frac{\ln \ln M(r)}{\ln r}$, where $M(r) = \max_{|z|=r} |f(z)|$.

To ensure the convergence of the infinite product, the canonical factor is introduced:

Mittag-Leffler's Theorem and Meromorphic Functions

Motivation: Infinite Sum of Fractions → Mittag-Leffler's Theorem → Partial Fractions of Special Functions → Application: Summation of Series → Numerical Example → Real-Life Application → Additional Aspects → Connection with Other Branches of Mathematics → Historical Background and Development of the Idea

A rational function $R(z) = P(z)/Q(z)$ is decomposed into a sum of simple fractions: $R = \sum A_k/(z - z_k)^{m_k} +$ a polynomial. Mittag-Leffler's theorem is an analogue for meromorphic functions with infinitely many poles: one can "prescribe" the poles and their principal parts and construct a...

Theorem (Mittag-Leffler, 1877): Let $\{a_n\}$ be a sequence of points without an accumulation point in $\mathbb{C}$ (i.e., $|a_n| \to \infty$), and for each $a_n$ a "principal part" $p_n\left(1/(z - a_n)\right)$ is given—a polynomial in $1/(z - a_n)$. Then there exists a meromorphic function $f$ ...

$ f(z) = h(z) + \sum_n \left[ p_n \left( \frac{1}{z - a_n} \right) - q_n(z) \right], $

where $h(z)$ is an arbitrary entire function, and $q_n(z)$ are polynomials ensuring the convergence of the series.

Laplace Transform and Complex Function Theory

Motivation: turn differentiation into multiplication → Definition and main properties → Inverse transform (Bromwich formula) → Connection with Complex Function Theory → Numerical example → Real application → Additional aspects → Connection with other areas of mathematics → Historical reference and development of the idea

Formulas

Step 1. Apply the Laplace transform to the equation. ℒ[δ(t)] = 1.Step 2. Y(s) = 1/(s²+2s+5). Complete the square: s²+2s+5 = (s+1)²+4.Step 4. Check by residues. The poles of Y(s)eˢᵗ are at s = −1±2i.
  • ·ℒ[1] = 1/s (Re s > 0)
  • ·ℒ[eᵃᵗ] = 1/(s−a) (Re s > Re a)
  • ·ℒ[sin(ωt)] = ω/(s²+ω²)
  • ·ℒ[cos(ωt)] = s/(s²+ω²)
  • ·ℒ[tⁿ] = n!/s^{n+1}
  • ·Linearity: ℒ[αf+βg] = αF + βG
  • ·Shift: ℒ[f'(t)] = sF(s) − f(0)
  • ·ℒ[f''(t)] = s²F(s) − sf(0) − f'(0)
  • ·Convolution: ℒ[(f*g)(t)] = F(s)·G(s)

Differential equations are the bane of mathematical physics. The Laplace transform replaces them with algebraic equations: differentiation ↦ multiplication by s. By solving the algebraic equation and applying the inverse transform (via residues!), we obtain the solution to the differential equati...

Here σ₀ is the abscissa of convergence (determined by the growth of f as t → ∞).

where summation is over all poles of F (in the left half-plane for stable systems).

The Laplace transform is a Fourier transform "with exponential weighting": F(σ+iω) = ℱ[e^{−σt}f(t)](ω). The poles of F(s) correspond to the system's frequencies; stability ⟺ all poles in the left half-plane (Re s < 0).